# [leetcode] Peeking Iterator

Peeking Iterator

Given an Iterator class interface with methods: `next()` and `hasNext()`, design and implement a PeekingIterator that support the `peek()` operation — it essentially peek() at the element that will be returned by the next call to next().

Here is an example. Assume that the iterator is initialized to the beginning of the list: `[1, 2, 3]`.

Call `next()` gets you 1, the first element in the list.

Now you call `peek()` and it returns 2, the next element. Calling `next()` after that still return 2.

You call `next()` the final time and it returns 3, the last element. Calling `hasNext()` after that should return false.

Hint:

1. Think of “looking ahead”. You want to cache the next element.
2. Is one variable sufficient? Why or why not?
3. Test your design with call order of `peek()` before `next()` vs `next()` before `peek()`.
4. For a clean implementation, check out Google’s guava library source code.

Follow up: How would you extend your design to be generic and work with all types, not just integer?

Credits:
Special thanks to @porker2008 for adding this problem and creating all test cases.

A very very interesting question, exams the class design skills of candidates.

We must store two variables, isPeeked and peekVal. Cache the peek value.

The syntax for calling a base function in inheritance class is

Base::foo()

rather than

super.foo()

```// Below is the interface for Iterator, which is already defined for you.
// **DO NOT** modify the interface for Iterator.
class Iterator {
struct Data;
Data* data;
public:
Iterator(const vector<int>& nums);
Iterator(const Iterator& iter);
virtual ~Iterator();
// Returns the next element in the iteration.
int next();
// Returns true if the iteration has more elements.
bool hasNext() const;
};

class PeekingIterator : public Iterator {
public:
int peekVal;
bool isPeeked;
PeekingIterator(const vector<int>& nums) : Iterator(nums) {
// Initialize any member here.
// **DO NOT** save a copy of nums and manipulate it directly.
// You should only use the Iterator interface methods.
isPeeked = false;
}

// Returns the next element in the iteration without advancing the iterator.
int peek() {
if(isPeeked){
return peekVal;
}
else{
isPeeked = true;
peekVal = Iterator::next();
return peekVal;
}
}

// hasNext() and next() should behave the same as in the Iterator interface.
// Override them if needed.
int next() {
if(isPeeked){
isPeeked = false;
return peekVal;
}
else{
return Iterator::next();
}
}

bool hasNext() const {
if(isPeeked || Iterator::hasNext()){
return true;
}
else{
return false;
}
}
};```

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